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50x^2=360
We move all terms to the left:
50x^2-(360)=0
a = 50; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·50·(-360)
Δ = 72000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72000}=\sqrt{14400*5}=\sqrt{14400}*\sqrt{5}=120\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{5}}{2*50}=\frac{0-120\sqrt{5}}{100} =-\frac{120\sqrt{5}}{100} =-\frac{6\sqrt{5}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{5}}{2*50}=\frac{0+120\sqrt{5}}{100} =\frac{120\sqrt{5}}{100} =\frac{6\sqrt{5}}{5} $
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